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[solved] eval a shell variable

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toralf
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Joined: 01 Feb 2004
Posts: 2104
Location: Hamburg/Germany

Posted: Thu Jan 31, 2008 10:36 am Post subject: [solved] eval a shell variable

I try something like this :

Code:

SQL_FOO="select * from foo"
SQL_BAR="select * from bar"

T="FOO"

RESULTS=`$SQL_$T`

Currently I get obviously not the result set from the DB.
My question is, how can I first create a variable name and after that use the _content_ the variable points to ?

Last edited by toralf on Sun Mar 16, 2008 8:19 pm; edited 1 time in total

Voltago
Advocate

Joined: 02 Sep 2003
Posts: 2482
Location: Hinter den Materiequellen

Posted: Thu Jan 31, 2008 11:15 am Post subject:

Code:

myvar=hello
varname=myvar
echo $varname
echo ${!varname}

Oh, and btw:
http://www.tldp.org/LDP/abs/html/

toralf
Advocate

Joined: 01 Feb 2004
Posts: 2104
Location: Hamburg/Germany

Posted: Thu Jan 31, 2008 12:12 pm Post subject:

thanks,
unfortunately I have to code this within ksh under IX 5.3 :-(

But this works :

Code:

[tfoerste@detlmtst01] /home/tfoerste> SQL_FOO="select count(id) from adm.agent"
[tfoerste@detlmtst01] /home/tfoerste> T=SQL_FOO
[tfoerste@detlmtst01] /home/tfoerste> eval $(echo db2 \$$T)

1
-----------
23756

1 record(s) selected.

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